What is the integral of 1/pi xsin(x) ?

The integral of 1/pi xsin(x) is 1/pi (-xcos(x)+sin(x))+C

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integral of 1/pi xsin(x)

\int \frac{1}{π} x sin (x) d x

\frac{1}{π} (- x cos (x) + sin (x)) + C

Solution steps

\int \frac{1}{π} x sin (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{π} \cdot \int x sin (x) d x

Apply Integration By Parts

: - x cos (x) - \int - cos (x) d x

= \frac{1}{π} (- x cos (x) - \int - cos (x) d x)

\int - cos (x) d x = - sin (x)

= \frac{1}{π} (- x cos (x) - (- sin (x)))

Simplify

= \frac{1}{π} (- x cos (x) + sin (x))

Add a constant to the solution

= \frac{1}{π} (- x cos (x) + sin (x)) + C

\int \frac{x}{2} - \frac{2}{x} d x

\int x (9 x^{2} - 5)^{\frac{3}{2}} d x

\int sin (5 x + 2) d x

\int \frac{1}{( 1 + x ^{2} )} d x

\int \frac{4 x ^{2} + x - 2}{x - 3} d x

What is the integral of 1/pi xsin(x) ?
The integral of 1/pi xsin(x) is 1/pi (-xcos(x)+sin(x))+C