What is the integral of (1+tan^2(β)) ?

The integral of (1+tan^2(β)) is tan(β)+C

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integral of (1+tan^2(β))

\int (1 + tan^{2} (β)) d β

tan (β) + C

Solution steps

\int 1 + tan^{2} (β) d β

Rewrite using trig identities

= \int sec^{2} (β) d β

Use the common integral:

\int sec^{2} (β) d β = tan (β)

= tan (β)

Add a constant to the solution

= tan (β) + C

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