What is the integral of 2x^2-cos(x)+C ?

The integral of 2x^2-cos(x)+C is (2x^3)/3-sin(x)+Cx+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of 2x^2-cos(x)+C

\int 2 x^{2} - cos (x) + C d x

\frac{2 x ^{3}}{3} - sin (x) + C x + C

Solution steps

\int 2 x^{2} - cos (x) + C d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 2 x^{2} d x - \int cos (x) d x + \int C d x

\int 2 x^{2} d x = \frac{2 x ^{3}}{3}

\int cos (x) d x = sin (x)

\int C d x = C x

= \frac{2 x ^{3}}{3} - sin (x) + C x

Add a constant to the solution

= \frac{2 x ^{3}}{3} - sin (x) + C x + C

\int cos (\frac{x}{6}) d x

\int cot^{5} (3 y) d y

\int \frac{2}{x ^{2} x ^{2} - 1} d x

\int (a^{2} - x^{2})^{3} d x

\int \frac{1}{3 x ^{2} + 27 x} d x

What is the integral of 2x^2-cos(x)+C ?
The integral of 2x^2-cos(x)+C is (2x^3)/3-sin(x)+Cx+C