What is the integral of sqrt(x^{17)} ?

The integral of sqrt(x^{17)} is 2/19 x^{19/2}+C

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integral of sqrt(x^{17)}

\int x^{17} d x

\frac{2}{19} x^{\frac{19}{2}} + C

Solution steps

\int x^{17} d x

x^{17} = x^{\frac{17}{2}},

assuming

x \geq 0

= \int x^{\frac{17}{2}} d x

Apply the Power Rule

: \frac{2}{19} x^{\frac{19}{2}}

= \frac{2}{19} x^{\frac{19}{2}}

Add a constant to the solution

= \frac{2}{19} x^{\frac{19}{2}} + C

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What is the integral of sqrt(x^{17)} ?
The integral of sqrt(x^{17)} is 2/19 x^{19/2}+C