What is the tangent of f(x)=x^3-2x+2,(4,58) ?

The tangent of f(x)=x^3-2x+2,(4,58) is y=46x-126

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tangent of f(x)=x^3-2x+2,(4,58)

tangent of

f (x) = x^{3} - 2 x + 2, (4, 58)

y = 46 x - 126

Solution steps

Find the slope of

f (x) = x^{3} - 2 x + 2 : \frac{df ( x )}{d x} = 3 x^{2} - 2

Compute the slope of

f (x) = x^{3} - 2 x + 2

(4, 58) : m = 46

Find the line with slope m=

46

and passing through

(4, 58) : y = 46 x - 126

y = 46 x - 126

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What is the tangent of f(x)=x^3-2x+2,(4,58) ?
The tangent of f(x)=x^3-2x+2,(4,58) is y=46x-126