What is the integral of 4*2^{-x}-1 ?

The integral of 4*2^{-x}-1 is -(2^{-x+2})/(ln(2))-x+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of 4*2^{-x}-1

\int 4 \cdot 2^{- x} - 1 d x

- \frac{2 ^{- x + 2}}{ln ( 2 )} - x + C

Solution steps

\int 4 \cdot 2^{- x} - 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 4 \cdot 2^{- x} d x - \int 1 d x

\int 4 \cdot 2^{- x} d x = - \frac{2 ^{- x + 2}}{ln ( 2 )}

\int 1 d x = x

= - \frac{2 ^{- x + 2}}{ln ( 2 )} - x

Add a constant to the solution

= - \frac{2 ^{- x + 2}}{ln ( 2 )} - x + C

\int sech^{3} (x) tanh (x) d x

\int sec^{2} (z) d z

\int \frac{x ^{4}}{( x ^{5} + 1 ) ^{4}} d x

\int (2 x^{3} + 1) x^{4} + 2 x d x

\int \frac{( 3 x ^{2} + 2 )}{x ^{2}} d x

What is the integral of 4*2^{-x}-1 ?
The integral of 4*2^{-x}-1 is -(2^{-x+2})/(ln(2))-x+C