What is the d/(dt)(6ln(cos(t))) ?

The d/(dt)(6ln(cos(t))) is -6tan(t)

What is the first d/(dt)(6ln(cos(t))) ?

The first d/(dt)(6ln(cos(t))) is -6tan(t)

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\frac{d}{d t} (6 ln (cos (t)))

- 6 tan (t)

Solution steps

\frac{d}{d t} (6 ln (cos (t)))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 6 \frac{d}{d t} (ln (cos (t)))

Apply the chain rule:

\frac{1}{cos ( t )} \frac{d}{d t} (cos (t))

= \frac{1}{cos ( t )} \frac{d}{d t} (cos (t))

\frac{d}{d t} (cos (t)) = - sin (t)

= 6 \cdot \frac{1}{cos ( t )} (- sin (t))

Simplify

6 \cdot \frac{1}{cos ( t )} (- sin (t)) : - 6 tan (t)

= - 6 tan (t)

\int \frac{( x + 4 )}{2 x + 3} d x

\int 5 e^{- 5 x} d x

\frac{d}{d x} (arctan (\frac{1}{1 + x ^{2}}))

\int_{- 5}^{5} 4 (25 - x^{2}) d x

8 x - 5

What is the d/(dt)(6ln(cos(t))) ?
The d/(dt)(6ln(cos(t))) is -6tan(t)
What is the first d/(dt)(6ln(cos(t))) ?
The first d/(dt)(6ln(cos(t))) is -6tan(t)