What is the integral of 4/((3-x)^2)+C ?

The integral of 4/((3-x)^2)+C is 4/(3-x)+Cx+C

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integral of 4/((3-x)^2)+C

\int \frac{4}{( 3 - x ) ^{2}} + C d x

\frac{4}{3 - x} + C x + C

Solution steps

\int \frac{4}{( 3 - x ) ^{2}} + C d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{4}{( 3 - x ) ^{2}} d x + \int C d x

\int \frac{4}{( 3 - x ) ^{2}} d x = \frac{4}{3 - x}

\int C d x = C x

= \frac{4}{3 - x} + C x

Add a constant to the solution

= \frac{4}{3 - x} + C x + C

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What is the integral of 4/((3-x)^2)+C ?
The integral of 4/((3-x)^2)+C is 4/(3-x)+Cx+C