What is the integral of ((x^2)/4)^2 ?

The integral of ((x^2)/4)^2 is (x^5)/(16)-(x^5)/(20)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of ((x^2)/4)^2

\int (\frac{x ^{2}}{4})^{2} d x

\frac{x ^{5}}{16} - \frac{x ^{5}}{20} + C

Solution steps

\int (\frac{x ^{2}}{4})^{2} d x

Apply Integration By Parts

: \frac{x ^{5}}{16} - \int \frac{x ^{4}}{4} d x

= \frac{x ^{5}}{16} - \int \frac{x ^{4}}{4} d x

\int \frac{x ^{4}}{4} d x = \frac{x ^{5}}{20}

= \frac{x ^{5}}{16} - \frac{x ^{5}}{20}

Add a constant to the solution

= \frac{x ^{5}}{16} - \frac{x ^{5}}{20} + C

\int \frac{( x + 1 )}{x ^{3} + 3 x ^{2} + 7 x + 5} d x

\int x \cdot (arctan (x))^{2} d x

\int \frac{1 + cos ( x )}{1 + sin ^{2} ( x )} d x

\int x^{3} 1 + 25 x^{2} d x

\int 1000 x + 250 d x

What is the integral of ((x^2)/4)^2 ?
The integral of ((x^2)/4)^2 is (x^5)/(16)-(x^5)/(20)+C