What is the integral of psqrt(p^2-25) ?

The integral of psqrt(p^2-25) is 1/3 (p^2-25)^{3/2}+C

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integral of psqrt(p^2-25)

\int p p^{2} - 25 d p

\frac{1}{3} (p^{2} - 25)^{\frac{3}{2}} + C

Solution steps

\int p p^{2} - 25 d p

Apply u-substitution

: \int u^{2} d u

= \int u^{2} d u

Apply the Power Rule

: \frac{u ^{3}}{3}

= \frac{u ^{3}}{3}

Substitute back

u = p^{2} - 25

= \frac{( p ^{2} - 25 ) ^{3}}{3}

Simplify

\frac{( p ^{2} - 25 ) ^{3}}{3} : \frac{1}{3} (p^{2} - 25)^{\frac{3}{2}}

= \frac{1}{3} (p^{2} - 25)^{\frac{3}{2}}

Add a constant to the solution

= \frac{1}{3} (p^{2} - 25)^{\frac{3}{2}} + C

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What is the integral of psqrt(p^2-25) ?
The integral of psqrt(p^2-25) is 1/3 (p^2-25)^{3/2}+C