What is the integral of (3x^4)/5 ?

The integral of (3x^4)/5 is (3x^5)/(25)+C

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integral of (3x^4)/5

\int \frac{3 x ^{4}}{5} d x

\frac{3 x ^{5}}{25} + C

Solution steps

\int \frac{3 x ^{4}}{5} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{3}{5} \cdot \int x^{4} d x

Apply the Power Rule

: \frac{x ^{5}}{5}

= \frac{3}{5} \cdot \frac{x ^{5}}{5}

Simplify

\frac{3}{5} \cdot \frac{x ^{5}}{5} : \frac{3 x ^{5}}{25}

= \frac{3 x ^{5}}{25}

Add a constant to the solution

= \frac{3 x ^{5}}{25} + C

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