What is the integral of (3x)/(sqrt(9-x^2)) ?

The integral of (3x)/(sqrt(9-x^2)) is -3sqrt(9-x^2)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (3x)/(sqrt(9-x^2))

\int \frac{3 x}{9 - x ^{2}} d x

- 3 9 - x^{2} + C

Solution steps

\int \frac{3 x}{9 - x ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \int \frac{x}{9 - x ^{2}} d x

Apply u-substitution

: \int - \frac{1}{2 u} d u

= 3 \cdot \int - \frac{1}{2 u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 (- \frac{1}{2} \cdot \int \frac{1}{u} d u)

Apply the Power Rule

: 2 u^{\frac{1}{2}}

= 3 (- \frac{1}{2} \cdot 2 u^{\frac{1}{2}})

Substitute back

u = 9 - x^{2}

= 3 (- \frac{1}{2} \cdot 2 (9 - x^{2})^{\frac{1}{2}})

Simplify

3 (- \frac{1}{2} \cdot 2 (9 - x^{2})^{\frac{1}{2}}) : - 3 9 - x^{2}

= - 3 9 - x^{2}

Add a constant to the solution

= - 3 9 - x^{2} + C

\int (2 x^{- 3} + x^{- 1}) d x

\int 6 x e^{- 2 x} d x

\int \frac{cos ( 4 x )}{e ^{s i n (4 x)}} d x

\int \frac{2 x ^{2}}{x ^{3} + 3} d x

\int \frac{( x ^{4} + 1 )}{x ^{5} + 5 x} d x

What is the integral of (3x)/(sqrt(9-x^2)) ?
The integral of (3x)/(sqrt(9-x^2)) is -3sqrt(9-x^2)+C