What is the integral of 1/(sin^2(x)+cos^2(x)) ?

The integral of 1/(sin^2(x)+cos^2(x)) is x+C

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integral of 1/(sin^2(x)+cos^2(x))

\int \frac{1}{sin ^{2} ( x ) + cos ^{2} ( x )} d x

x + C

Solution steps

\int \frac{1}{sin ^{2} ( x ) + cos ^{2} ( x )} d x

Rewrite using trig identities

= \int 1 d x

Integral of a constant:

\int a d x = a x

= 1 \cdot x

Simplify

= x

Add a constant to the solution

= x + C

\int \frac{( cos ( x ) ) ^{2}}{sin ( x )} d x

\int x + \frac{1}{x ^{3}} - 3 e^{3 x} d x

\int sin (3 x + π) d x

\int \frac{x - 1}{2 x + x + 1} d x

\int \frac{2}{1 + sin ( x )} d x

What is the integral of 1/(sin^2(x)+cos^2(x)) ?
The integral of 1/(sin^2(x)+cos^2(x)) is x+C