What is the integral of sqrt(x^{15)} ?

The integral of sqrt(x^{15)} is 2/17 x^{17/2}+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of sqrt(x^{15)}

\int x^{15} d x

\frac{2}{17} x^{\frac{17}{2}} + C

Solution steps

\int x^{15} d x

x^{15} = x^{\frac{15}{2}},

assuming

x \geq 0

= \int x^{\frac{15}{2}} d x

Apply the Power Rule

: \frac{2}{17} x^{\frac{17}{2}}

= \frac{2}{17} x^{\frac{17}{2}}

Add a constant to the solution

= \frac{2}{17} x^{\frac{17}{2}} + C

\int \frac{x ^{2}}{x ^{2} + 2 x - 3} d x

\int ln (t^{2}) d t

\int \frac{x}{x ^{4} - x ^{2} - 2} d x

\int 2 x + cos (x) d x

\int \frac{1}{cos ^{2} ( 5 x + 3 )} d x

What is the integral of sqrt(x^{15)} ?
The integral of sqrt(x^{15)} is 2/17 x^{17/2}+C