What is the integral of 9cos(pix) ?

The integral of 9cos(pix) is 9/pi sin(pix)+C

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integral of 9cos(pix)

\int 9 cos (π x) d x

\frac{9}{π} sin (π x) + C

Solution steps

\int 9 cos (π x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 9 \cdot \int cos (π x) d x

Apply u-substitution

: \int cos (u) \frac{1}{π} d u

= 9 \cdot \int cos (u) \frac{1}{π} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 9 \cdot \frac{1}{π} \cdot \int cos (u) d u

Use the common integral:

\int cos (u) d u = sin (u)

= 9 \cdot \frac{1}{π} sin (u)

Substitute back

u = π x

= 9 \cdot \frac{1}{π} sin (π x)

Simplify

9 \cdot \frac{1}{π} sin (π x) : \frac{9}{π} sin (π x)

= \frac{9}{π} sin (π x)

Add a constant to the solution

= \frac{9}{π} sin (π x) + C

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What is the integral of 9cos(pix) ?
The integral of 9cos(pix) is 9/pi sin(pix)+C