What is the (x^4(x-3)^3)^' ?

The (x^4(x-3)^3)^' is 4x^3(x-3)^3+3(x-3)^2x^4

What is the first (x^4(x-3)^3)^' ?

The first (x^4(x-3)^3)^' is 4x^3(x-3)^3+3(x-3)^2x^4

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(x^{4} (x - 3)^{3})^{^{'}}

4 x^{3} (x - 3)^{3} + 3 (x - 3)^{2} x^{4}

Solution steps

(x^{4} (x - 3)^{3})^{'}

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x^{4}, g = (x - 3)^{3}

= (x^{4})^{^{'}} (x - 3)^{3} + ((x - 3)^{3})^{^{'}} x^{4}

(x^{4})^{'} = 4 x^{3}

((x - 3)^{3})^{'} = 3 (x - 3)^{2}

= 4 x^{3} (x - 3)^{3} + 3 (x - 3)^{2} x^{4}

\int - \frac{1}{y ^{2}} d y

\frac{d}{d x} (cos (7 x) \cdot 7)

\int (10 sin (5 x)) d x

\frac{d}{d x} (6 \cdot 3^{x})

y = 2 - \frac{x}{2}, x = 2 y^{2}

What is the (x^4(x-3)^3)^' ?
The (x^4(x-3)^3)^' is 4x^3(x-3)^3+3(x-3)^2x^4
What is the first (x^4(x-3)^3)^' ?
The first (x^4(x-3)^3)^' is 4x^3(x-3)^3+3(x-3)^2x^4