What is the integral of (ln(x^2+1))/(x^2) ?

The integral of (ln(x^2+1))/(x^2) is -(ln(x^2+1))/x+2arctan(x)+C

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integral of (ln(x^2+1))/(x^2)

\int \frac{ln ( x ^{2} + 1 )}{x ^{2}} d x

- \frac{ln ( x ^{2} + 1 )}{x} + 2 arctan (x) + C

Solution steps

\int \frac{ln ( x ^{2} + 1 )}{x ^{2}} d x

Apply Integration By Parts

: - \frac{ln ( x ^{2} + 1 )}{x} - \int - \frac{2}{x ^{2} + 1} d x

= - \frac{ln ( x ^{2} + 1 )}{x} - \int - \frac{2}{x ^{2} + 1} d x

\int - \frac{2}{x ^{2} + 1} d x = - 2 arctan (x)

= - \frac{ln ( x ^{2} + 1 )}{x} - (- 2 arctan (x))

Simplify

= - \frac{ln ( x ^{2} + 1 )}{x} + 2 arctan (x)

Add a constant to the solution

= - \frac{ln ( x ^{2} + 1 )}{x} + 2 arctan (x) + C

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What is the integral of (ln(x^2+1))/(x^2) ?
The integral of (ln(x^2+1))/(x^2) is -(ln(x^2+1))/x+2arctan(x)+C