What is the integral of 2tan(2x) ?

The integral of 2tan(2x) is -ln|cos(2x)|+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of 2tan(2x)

\int 2 tan (2 x) d x

- ln ∣ cos (2 x) ∣ + C

Solution steps

\int 2 tan (2 x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int tan (2 x) d x

Rewrite using trig identities

= 2 \cdot \int \frac{sin ( 2 x )}{cos ( 2 x )} d x

Apply u-substitution

: \int - \frac{1}{2 u} d u

= 2 \cdot \int - \frac{1}{2 u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 (- \frac{1}{2} \cdot \int \frac{1}{u} d u)

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= 2 (- \frac{1}{2} ln ∣ u ∣)

Substitute back

u = cos (2 x)

= 2 (- \frac{1}{2} ln ∣ cos (2 x) ∣)

Simplify

2 (- \frac{1}{2} ln ∣ cos (2 x) ∣) : - ln ∣ cos (2 x) ∣

= - ln ∣ cos (2 x) ∣

Add a constant to the solution

= - ln ∣ cos (2 x) ∣ + C

\int \frac{( x ^{2} cos ( x ) - 2 x sin ( x ) )}{x ^{4}} d x

\int (8 x^{3} + 7 3 x^{2}) d x

\int \frac{1}{( 1 - 2 x ) ^{3}} d x

\int x^{8} e^{x^{2}} d x

\int \frac{x ^{2} + 1}{x ^{3} + x ^{2} - x - 1} d x