What is the integral of e^{2x}4x ?

The integral of e^{2x}4x is 2e^{2x}x-e^{2x}+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of e^{2x}4x

\int e^{2 x} 4 x d x

2 e^{2 x} x - e^{2 x} + C

Solution steps

\int e^{2 x} \cdot 4 x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 4 \cdot \int e^{2 x} x d x

Apply u-substitution

: \int \frac{e ^{u} u}{4} d u

= 4 \cdot \int \frac{e ^{u} u}{4} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 4 \cdot \frac{1}{4} \cdot \int e^{u} u d u

Apply Integration By Parts

: e^{u} u - \int e^{u} d u

= 4 \cdot \frac{1}{4} (e^{u} u - \int e^{u} d u)

\int e^{u} d u = e^{u}

= 4 \cdot \frac{1}{4} (e^{u} u - e^{u})

Substitute back

u = 2 x

= 4 \cdot \frac{1}{4} (e^{2 x} \cdot 2 x - e^{2 x})

Simplify

4 \cdot \frac{1}{4} (e^{2 x} \cdot 2 x - e^{2 x}) : 2 e^{2 x} x - e^{2 x}

= 2 e^{2 x} x - e^{2 x}

Add a constant to the solution

= 2 e^{2 x} x - e^{2 x} + C

\int - x^{2} - 2 x + 3 d x

\int (x + 17) 34 x + x^{2} d x

\int \frac{2}{( x - 3 ) ^{4}} d x

\int \frac{2}{4 - x ^{2}} d x

\int \frac{e ^{x}}{1 - 2 e ^{x}} d x

What is the integral of e^{2x}4x ?
The integral of e^{2x}4x is 2e^{2x}x-e^{2x}+C