What is the integral of 2x^2-2x-4 ?

The integral of 2x^2-2x-4 is (2x^3)/3-x^2-4x+C

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integral of 2x^2-2x-4

\int 2 x^{2} - 2 x - 4 d x

\frac{2 x ^{3}}{3} - x^{2} - 4 x + C

Solution steps

\int 2 x^{2} - 2 x - 4 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 2 x^{2} d x - \int 2 x d x - \int 4 d x

\int 2 x^{2} d x = \frac{2 x ^{3}}{3}

\int 2 x d x = x^{2}

\int 4 d x = 4 x

= \frac{2 x ^{3}}{3} - x^{2} - 4 x

Add a constant to the solution

= \frac{2 x ^{3}}{3} - x^{2} - 4 x + C

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What is the integral of 2x^2-2x-4 ?
The integral of 2x^2-2x-4 is (2x^3)/3-x^2-4x+C