What is the integral of 1/(1+e^2) ?

The integral of 1/(1+e^2) is 1/(1+e^2)x+C

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integral of 1/(1+e^2)

\int \frac{1}{1 + e ^{2}} d x

\frac{1}{1 + e ^{2}} x + C

Solution steps

\int \frac{1}{1 + e ^{2}} d x

Integral of a constant:

\int a d x = a x

= \frac{1}{1 + e ^{2}} x

Add a constant to the solution

= \frac{1}{1 + e ^{2}} x + C

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