What is the integral of 9((sin(2x))/(sin(x))) ?

The integral of 9((sin(2x))/(sin(x))) is 18sin(x)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of 9((sin(2x))/(sin(x)))

\int 9 (\frac{sin ( 2 x )}{sin ( x )}) d x

18 sin (x) + C

Solution steps

\int 9 \cdot \frac{sin ( 2 x )}{sin ( x )} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 9 \cdot \int \frac{sin ( 2 x )}{sin ( x )} d x

Rewrite using trig identities

= 9 \cdot \int 2 cos (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 9 \cdot 2 \cdot \int cos (x) d x

Use the common integral:

\int cos (x) d x = sin (x)

= 9 \cdot 2 sin (x)

Simplify

= 18 sin (x)

Add a constant to the solution

= 18 sin (x) + C

\int x sin (\frac{π x}{2}) d x

\int sin^{4} (t) cos (t) d t

\int 3 x (x^{2} + 4)^{2} d x

\int 9 sin (2 x) d x

\int (4 x^{2} + 8)^{2} d x

What is the integral of 9((sin(2x))/(sin(x))) ?
The integral of 9((sin(2x))/(sin(x))) is 18sin(x)+C