What is the integral from 0 to 2 of f(x^3) ?

The integral from 0 to 2 of f(x^3) is f*4

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integral from 0 to 2 of f(x^3)

\int_{0}^{2} f (x^{3}) d x

f \cdot 4

Solution steps

\int_{0}^{2} f x^{3} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= f \cdot \int_{0}^{2} x^{3} d x

Apply the Power Rule

: [\frac{x ^{4}}{4}]_{0}^{2}

= f [\frac{x ^{4}}{4}]_{0}^{2}

Compute the boundaries:

4

= f \cdot 4

\frac{d ^{2} x}{d x ^{2}}

x y^{^{'}} + 2 y = \frac{3 e ^{- 4 x}}{x}

x \to - 1 + lim (\frac{x}{x ^{2} - 1})

\int_{0}^{4} 5 e^{- x^{2}} d x

\frac{cot ( x )}{x}

What is the integral from 0 to 2 of f(x^3) ?
The integral from 0 to 2 of f(x^3) is f*4