What is the integral of (sin(x))/(3-2cos(x)) ?

The integral of (sin(x))/(3-2cos(x)) is 1/2 ln|3-2cos(x)|+C

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integral of (sin(x))/(3-2cos(x))

\int \frac{sin ( x )}{3 - 2 cos ( x )} d x

\frac{1}{2} ln ∣ 3 - 2 cos (x) ∣ + C

Solution steps

\int \frac{sin ( x )}{3 - 2 cos ( x )} d x

Apply u-substitution

: \int \frac{1}{2 u} d u

= \int \frac{1}{2 u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int \frac{1}{u} d u

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= \frac{1}{2} ln ∣ u ∣

Substitute back

u = 3 - 2 cos (x)

= \frac{1}{2} ln ∣ 3 - 2 cos (x) ∣

Add a constant to the solution

= \frac{1}{2} ln ∣ 3 - 2 cos (x) ∣ + C

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What is the integral of (sin(x))/(3-2cos(x)) ?
The integral of (sin(x))/(3-2cos(x)) is 1/2 ln|3-2cos(x)|+C