What is the integral of sqrt(1+t) ?

The integral of sqrt(1+t) is 2/3 (1+t)^{3/2}+C

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integral of sqrt(1+t)

\int 1 + t d t

\frac{2}{3} (1 + t)^{\frac{3}{2}} + C

Solution steps

\int 1 + t d t

Apply u-substitution

: \int u d u

= \int u d u

Apply the Power Rule

: \frac{2}{3} u^{\frac{3}{2}}

= \frac{2}{3} u^{\frac{3}{2}}

Substitute back

u = 1 + t

= \frac{2}{3} (1 + t)^{\frac{3}{2}}

Add a constant to the solution

= \frac{2}{3} (1 + t)^{\frac{3}{2}} + C

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What is the integral of sqrt(1+t) ?
The integral of sqrt(1+t) is 2/3 (1+t)^{3/2}+C