What is expand (-2cos(2x)-sin(3x))^2 ?

The solution to expand (-2cos(2x)-sin(3x))^2 is 4cos^2(2x)+4cos(2x)sin(3x)+sin^2(3x)

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expand (-2cos(2x)-sin(3x))^2

expand

(- 2 cos (2 x) - sin (3 x))^{2}

4 cos^{2} (2 x) + 4 cos (2 x) sin (3 x) + sin^{2} (3 x)

Solution steps

(- 2 cos (2 x) - sin (3 x))^{2}

Apply Perfect Square Formula:

(a - b)^{2} = a^{2} - 2 ab + b^{2}

(- 2 cos (2 x) - sin (3 x))^{2} = (- 2 cos (2 x))^{2} - 2 (- 2 cos (2 x)) sin (3 x) + sin^{2} (3 x)

= (- 2 cos (2 x))^{2} - 2 (- 2 cos (2 x)) sin (3 x) + sin^{2} (3 x)

Simplify

(- 2 cos (2 x))^{2} - 2 (- 2 cos (2 x)) sin (3 x) + sin^{2} (3 x) : 4 cos^{2} (2 x) + 4 cos (2 x) sin (3 x) + sin^{2} (3 x)

= 4 cos^{2} (2 x) + 4 cos (2 x) sin (3 x) + sin^{2} (3 x)

x \to \frac{1}{2} lim (arcsin (x))

f (x) = x^{2} + x - 3

3 t^{4} y^{^{''}} + 7 t^{3} y^{^{'}} = 0

n = 0 \sum \infty \frac{1}{( n + 10 )}

\int 14 tan^{3} (x) d x

What is expand (-2cos(2x)-sin(3x))^2 ?
The solution to expand (-2cos(2x)-sin(3x))^2 is 4cos^2(2x)+4cos(2x)sin(3x)+sin^2(3x)