What is the integral of (x+1)^{20} ?

The integral of (x+1)^{20} is ((x+1)^{21})/(21)+C

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integral of (x+1)^{20}

\int (x + 1)^{20} d x

\frac{( x + 1 ) ^{21}}{21} + C

Solution steps

\int (x + 1)^{20} d x

Apply u-substitution

: \int u^{20} d u

= \int u^{20} d u

Apply the Power Rule

: \frac{u ^{21}}{21}

= \frac{u ^{21}}{21}

Substitute back

u = x + 1

= \frac{( x + 1 ) ^{21}}{21}

Add a constant to the solution

= \frac{( x + 1 ) ^{21}}{21} + C

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What is the integral of (x+1)^{20} ?
The integral of (x+1)^{20} is ((x+1)^{21})/(21)+C