What is the integral of e^{2x}-6x ?

The integral of e^{2x}-6x is 1/2 e^{2x}-3x^2+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of e^{2x}-6x

\int e^{2 x} - 6 x d x

\frac{1}{2} e^{2 x} - 3 x^{2} + C

Solution steps

\int e^{2 x} - 6 x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int e^{2 x} d x - \int 6 x d x

\int e^{2 x} d x = \frac{1}{2} e^{2 x}

\int 6 x d x = 3 x^{2}

= \frac{1}{2} e^{2 x} - 3 x^{2}

Add a constant to the solution

= \frac{1}{2} e^{2 x} - 3 x^{2} + C

\int \frac{1}{x} ln (x) d x

\int (\frac{( ln ( x ) ) ^{8}}{x}) d x

\int 5 ln (\frac{x}{5}) d x

\int \frac{x - 3}{3 x ^{2} + 6 x + 2} d x

What is the integral of e^{2x}-6x ?
The integral of e^{2x}-6x is 1/2 e^{2x}-3x^2+C