What is the integral of (x^5-pi^5+x^2-pi^2) ?

The integral of (x^5-pi^5+x^2-pi^2) is (x^6)/6-pi^5x+(x^3)/3-pi^2x+C

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integral of (x^5-pi^5+x^2-pi^2)

\int (x^{5} - π^{5} + x^{2} - π^{2}) d x

\frac{x ^{6}}{6} - π^{5} x + \frac{x ^{3}}{3} - π^{2} x + C

Solution steps

\int x^{5} - π^{5} + x^{2} - π^{2} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x^{5} d x - \int π^{5} d x + \int x^{2} d x - \int π^{2} d x

\int x^{5} d x = \frac{x ^{6}}{6}

\int π^{5} d x = π^{5} x

\int x^{2} d x = \frac{x ^{3}}{3}

\int π^{2} d x = π^{2} x

= \frac{x ^{6}}{6} - π^{5} x + \frac{x ^{3}}{3} - π^{2} x

Add a constant to the solution

= \frac{x ^{6}}{6} - π^{5} x + \frac{x ^{3}}{3} - π^{2} x + C

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What is the integral of (x^5-pi^5+x^2-pi^2) ?
The integral of (x^5-pi^5+x^2-pi^2) is (x^6)/6-pi^5x+(x^3)/3-pi^2x+C