What is the integral of sec^3(p)tan(p) ?

The integral of sec^3(p)tan(p) is 1/3 sec^3(p)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of sec^3(p)tan(p)

\int sec^{3} (p) tan (p) d p

\frac{1}{3} sec^{3} (p) + C

Solution steps

\int sec^{3} (p) tan (p) d p

Apply u-substitution

: \int \frac{1}{3} d u

= \int \frac{1}{3} d u

Integral of a constant:

\int a d x = a x

= \frac{1}{3} u

Substitute back

u = sec^{3} (p)

= \frac{1}{3} sec^{3} (p)

Add a constant to the solution

= \frac{1}{3} sec^{3} (p) + C

\int \frac{3 + 4 x ^{\frac{3}{2}}}{x} d x

\int 1080 e^{- 0.9 x} d x

\int \frac{5 x - 5}{3 x ^{2} - 8 x - 3} d x

\int cos (2 sin (x)) cos (x) d x

\int csc^{2} (3 x) cot (3 x) d x

What is the integral of sec^3(p)tan(p) ?
The integral of sec^3(p)tan(p) is 1/3 sec^3(p)+C