What is the integral of-8cos(x) ?

The integral of-8cos(x) is -8sin(x)+C

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integral of-8cos(x)

\int - 8 cos (x) d x

- 8 sin (x) + C

Solution steps

\int - 8 cos (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 8 \cdot \int cos (x) d x

Use the common integral:

\int cos (x) d x = sin (x)

= - 8 sin (x)

Add a constant to the solution

= - 8 sin (x) + C

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