What is the integral of arccot(g)x ?

The integral of arccot(g)x is 1/2 x^2arccot(g)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of arccot(g)x

\int arccot (g) x d x

\frac{1}{2} x^{2} arccot (g) + C

Solution steps

\int arccot (g) x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= arccot (g) \cdot \int x d x

Apply the Power Rule

: \frac{x ^{2}}{2}

= arccot (g) \frac{x ^{2}}{2}

Simplify

arccot (g) \frac{x ^{2}}{2} : \frac{1}{2} x^{2} arccot (g)

= \frac{1}{2} x^{2} arccot (g)

Add a constant to the solution

= \frac{1}{2} x^{2} arccot (g) + C

\int \frac{7}{x ^{2} + x - 12} d x

\int \frac{x - 1}{x ^{2} + 2 x + 2} d x

\int - sin (4 x) d x

\int 2 x \cdot ln^{2} (x) d x

\int \frac{1 - x ^{2}}{2 x} d x

What is the integral of arccot(g)x ?
The integral of arccot(g)x is 1/2 x^2arccot(g)+C