What is the integral of-8x^{-1} ?

The integral of-8x^{-1} is -8ln|x|+C

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integral of-8x^{-1}

\int - 8 x^{- 1} d x

- 8 ln ∣ x ∣ + C

Solution steps

\int - 8 x^{- 1} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 8 \cdot \int x^{- 1} d x

Use the common integral:

\int x^{- 1} d x = ln (∣ x ∣)

= - 8 ln ∣ x ∣

Add a constant to the solution

= - 8 ln ∣ x ∣ + C

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