What is the integral of ((12)/(1+x^2)) ?

The integral of ((12)/(1+x^2)) is 12arctan(x)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of ((12)/(1+x^2))

\int (\frac{12}{1 + x ^{2}}) d x

12 arctan (x) + C

Solution steps

\int \frac{12}{1 + x ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 12 \cdot \int \frac{1}{1 + x ^{2}} d x

Use the common integral:

\int \frac{1}{1 + x ^{2}} d x = arctan (x)

= 12 arctan (x)

Add a constant to the solution

= 12 arctan (x) + C

\int \frac{cos ( x )}{sin ^{7} ( x )} d x

\int e^{t} \cdot cos (t) d t

\int \frac{5}{( 5 x + 3 ) ln ( 5 x + 3 )} d x

\int - arctan (x) d x

\int \frac{1}{- x} d x

What is the integral of ((12)/(1+x^2)) ?
The integral of ((12)/(1+x^2)) is 12arctan(x)+C