What is the integral of sec(4x+2)tan(4x+2) ?

The integral of sec(4x+2)tan(4x+2) is 1/4 sec(4x+2)+C

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integral of sec(4x+2)tan(4x+2)

\int sec (4 x + 2) tan (4 x + 2) d x

\frac{1}{4} sec (4 x + 2) + C

Solution steps

\int sec (4 x + 2) tan (4 x + 2) d x

Apply u-substitution

: \int sec (u) tan (u) \frac{1}{4} d u

= \int sec (u) tan (u) \frac{1}{4} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{4} \cdot \int sec (u) tan (u) d u

Apply u-substitution

: \int 1 d v

= \frac{1}{4} \cdot \int 1 d v

Integral of a constant:

\int a d x = a x

= \frac{1}{4} \cdot 1 \cdot v

Substitute back

= \frac{1}{4} \cdot 1 \cdot sec (4 x + 2)

Simplify

= \frac{1}{4} sec (4 x + 2)

Add a constant to the solution

= \frac{1}{4} sec (4 x + 2) + C

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What is the integral of sec(4x+2)tan(4x+2) ?
The integral of sec(4x+2)tan(4x+2) is 1/4 sec(4x+2)+C