What is the integral of (x^2+sin^2(x))/(x^2sin^2(x)) ?

The integral of (x^2+sin^2(x))/(x^2sin^2(x)) is -cot(x)-1/x+C

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integral of (x^2+sin^2(x))/(x^2sin^2(x))

\int \frac{x ^{2} + sin ^{2} ( x )}{x ^{2} sin ^{2} ( x )} d x

- cot (x) - \frac{1}{x} + C

Solution steps

\int \frac{x ^{2} + sin ^{2} ( x )}{x ^{2} sin ^{2} ( x )} d x

Expand

\frac{x ^{2} + sin ^{2} ( x )}{x ^{2} sin ^{2} ( x )} : \frac{1}{sin ^{2} ( x )} + \frac{1}{x ^{2}}

= \int \frac{1}{sin ^{2} ( x )} + \frac{1}{x ^{2}} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{1}{sin ^{2} ( x )} d x + \int \frac{1}{x ^{2}} d x

\int \frac{1}{sin ^{2} ( x )} d x = - cot (x)

\int \frac{1}{x ^{2}} d x = - \frac{1}{x}

= - cot (x) - \frac{1}{x}

Add a constant to the solution

= - cot (x) - \frac{1}{x} + C

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What is the integral of (x^2+sin^2(x))/(x^2sin^2(x)) ?
The integral of (x^2+sin^2(x))/(x^2sin^2(x)) is -cot(x)-1/x+C