What is the integral of 1/(xsqrt(x^2)) ?

The integral of 1/(xsqrt(x^2)) is -1/x+C

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integral of 1/(xsqrt(x^2))

\int \frac{1}{x x ^{2}} d x

- \frac{1}{x} + C

Solution steps

\int \frac{1}{x x ^{2}} d x

x^{2} = (x),

assuming

x \geq 0

= \int \frac{1}{xx} d x

xx = x^{2}

= \int \frac{1}{x ^{2}} d x

Apply the Power Rule

: - \frac{1}{x}

= - \frac{1}{x}

Add a constant to the solution

= - \frac{1}{x} + C

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What is the integral of 1/(xsqrt(x^2)) ?
The integral of 1/(xsqrt(x^2)) is -1/x+C