What is the integral of x^2(2x-1)^2 ?

The integral of x^2(2x-1)^2 is (4x^5)/5-x^4+(x^3)/3+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of x^2(2x-1)^2

\int x^{2} (2 x - 1)^{2} d x

\frac{4 x ^{5}}{5} - x^{4} + \frac{x ^{3}}{3} + C

Solution steps

\int x^{2} (2 x - 1)^{2} d x

Expand

x^{2} (2 x - 1)^{2} : 4 x^{4} - 4 x^{3} + x^{2}

= \int 4 x^{4} - 4 x^{3} + x^{2} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 4 x^{4} d x - \int 4 x^{3} d x + \int x^{2} d x

\int 4 x^{4} d x = \frac{4 x ^{5}}{5}

\int 4 x^{3} d x = x^{4}

\int x^{2} d x = \frac{x ^{3}}{3}

= \frac{4 x ^{5}}{5} - x^{4} + \frac{x ^{3}}{3}

Add a constant to the solution

= \frac{4 x ^{5}}{5} - x^{4} + \frac{x ^{3}}{3} + C

\int 3 x^{2} arctan (x) d x

\int 8 cos (π x) d x

\int e^{\frac{- 2}{x}} d x

\int \frac{1}{100 - 49 x ^{2}} d x

\int \frac{1}{x 144 x ^{2} - 1} d x

What is the integral of x^2(2x-1)^2 ?
The integral of x^2(2x-1)^2 is (4x^5)/5-x^4+(x^3)/3+C