What is the integral of (4x^3-7sqrt(x))/x ?

The integral of (4x^3-7sqrt(x))/x is (4x^3)/3-14sqrt(x)+C

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integral of (4x^3-7sqrt(x))/x

\int \frac{4 x ^{3} - 7 x}{x} d x

\frac{4 x ^{3}}{3} - 14 x + C

Solution steps

\int \frac{4 x ^{3} - 7 x}{x} d x

Expand

\frac{4 x ^{3} - 7 x}{x} : 4 x^{2} - \frac{7}{x}

= \int 4 x^{2} - \frac{7}{x} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 4 x^{2} d x - \int \frac{7}{x} d x

\int 4 x^{2} d x = \frac{4 x ^{3}}{3}

\int \frac{7}{x} d x = 14 x

= \frac{4 x ^{3}}{3} - 14 x

Add a constant to the solution

= \frac{4 x ^{3}}{3} - 14 x + C

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What is the integral of (4x^3-7sqrt(x))/x ?
The integral of (4x^3-7sqrt(x))/x is (4x^3)/3-14sqrt(x)+C