What is the integral of (x^{(3/2)}+2x+1) ?

The integral of (x^{(3/2)}+2x+1) is 2/5 x^{5/2}+x^2+x+C

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integral of (x^{(3/2)}+2x+1)

\int (x^{(\frac{3}{2})} + 2 x + 1) d x

\frac{2}{5} x^{\frac{5}{2}} + x^{2} + x + C

Solution steps

\int x^{\frac{3}{2}} + 2 x + 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x^{\frac{3}{2}} d x + \int 2 x d x + \int 1 d x

\int x^{\frac{3}{2}} d x = \frac{2}{5} x^{\frac{5}{2}}

\int 2 x d x = x^{2}

\int 1 d x = x

= \frac{2}{5} x^{\frac{5}{2}} + x^{2} + x

Add a constant to the solution

= \frac{2}{5} x^{\frac{5}{2}} + x^{2} + x + C

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What is the integral of (x^{(3/2)}+2x+1) ?
The integral of (x^{(3/2)}+2x+1) is 2/5 x^{5/2}+x^2+x+C