What is the integral of (x^{-2})/2 ?

The integral of (x^{-2})/2 is -1/(2x)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (x^{-2})/2

\int \frac{x ^{- 2}}{2} d x

- \frac{1}{2 x} + C

Solution steps

\int \frac{x ^{- 2}}{2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int x^{- 2} d x

Apply the Power Rule

: - \frac{1}{x}

= \frac{1}{2} (- \frac{1}{x})

Simplify

\frac{1}{2} (- \frac{1}{x}) : - \frac{1}{2 x}

= - \frac{1}{2 x}

Add a constant to the solution

= - \frac{1}{2 x} + C

\int t (2 t + 7)^{\frac{1}{3}} d t

\int x^{2 n + 1} d x

\int 4 x^{4} e^{6 x^{5}} d x

\int \frac{1}{x ^{2} - x - 12} d x

\int \frac{3 x + 1}{x ^{3} + x} d x