What is the integral of (1/(x+2)) ?

The integral of (1/(x+2)) is ln|x+2|+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (1/(x+2))

\int (\frac{1}{x + 2}) d x

ln ∣ x + 2 ∣ + C

Solution steps

\int \frac{1}{x + 2} d x

Apply u-substitution

: \int \frac{1}{u} d u

= \int \frac{1}{u} d u

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= ln ∣ u ∣

Substitute back

u = x + 2

= ln ∣ x + 2 ∣

Add a constant to the solution

= ln ∣ x + 2 ∣ + C

\int (x + x)^{2} + 8 e^{2 x} d x

\int \frac{5}{8 x - x ^{2}} d x

\int x^{3} x^{2} d x

\int sin^{3} (x) sec^{3} (x) d x

\int \frac{2 x ^{2} - x + 1}{2 x ^{2} - 3 x + 1} d x