What is the integral of-2t^4e^{6t^5} ?

The integral of-2t^4e^{6t^5} is -1/15 e^{6t^5}+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of-2t^4e^{6t^5}

\int - 2 t^{4} e^{6 t^{5}} d t

- \frac{1}{15} e^{6 t^{5}} + C

Solution steps

\int - 2 t^{4} e^{6 t^{5}} d t

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 2 \cdot \int t^{4} e^{6 t^{5}} d t

Apply u-substitution

: \int \frac{e ^{6 u^{\frac{5}{4}}} u ^{\frac{1}{4}}}{4} d u

= - 2 \cdot \int \frac{e ^{6 u^{\frac{5}{4}}} u ^{\frac{1}{4}}}{4} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 2 \cdot \frac{1}{4} \cdot \int e^{6 u^{\frac{5}{4}}} u^{\frac{1}{4}} d u

Apply u-substitution

: \int \frac{4 e ^{6 v}}{5} d v

= - 2 \cdot \frac{1}{4} \cdot \int \frac{4 e ^{6 v}}{5} d v

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 2 \cdot \frac{1}{4} \cdot \frac{4}{5} \cdot \int e^{6 v} d v

Apply u-substitution

: \int e^{w} \frac{1}{6} d w

= - 2 \cdot \frac{1}{4} \cdot \frac{4}{5} \cdot \int e^{w} \frac{1}{6} d w

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 2 \cdot \frac{1}{4} \cdot \frac{4}{5} \cdot \frac{1}{6} \cdot \int e^{w} d w

Use the common integral:

\int e^{w} d w = e^{w}

= - 2 \cdot \frac{1}{4} \cdot \frac{4}{5} \cdot \frac{1}{6} e^{w}

Substitute back

= - 2 \cdot \frac{1}{4} \cdot \frac{4}{5} \cdot \frac{1}{6} e^{6 (t^{4})^{\frac{5}{4}}}

Simplify

- 2 \cdot \frac{1}{4} \cdot \frac{4}{5} \cdot \frac{1}{6} e^{6 (t^{4})^{\frac{5}{4}}} : - \frac{1}{15} e^{6 t^{5}}

= - \frac{1}{15} e^{6 t^{5}}

Add a constant to the solution

= - \frac{1}{15} e^{6 t^{5}} + C

\int e^{2 x} e^{3 x} d x

\int (3 x^{2} + 2)^{2} d x

\int - t d t

\int sin^{2} (x) e^{x} d x

What is the integral of-2t^4e^{6t^5} ?
The integral of-2t^4e^{6t^5} is -1/15 e^{6t^5}+C