What is the integral of (2x)/4 ?

The integral of (2x)/4 is (x^2)/4+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (2x)/4

\int \frac{2 x}{4} d x

\frac{x ^{2}}{4} + C

Solution steps

\int \frac{2 x}{4} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{2}{4} \cdot \int x d x

Cancel the common factor:

2

= \frac{1}{2} \cdot \int x d x

Apply the Power Rule

: \frac{x ^{2}}{2}

= \frac{1}{2} \cdot \frac{x ^{2}}{2}

Simplify

\frac{1}{2} \cdot \frac{x ^{2}}{2} : \frac{x ^{2}}{4}

= \frac{x ^{2}}{4}

Add a constant to the solution

= \frac{x ^{2}}{4} + C

\int x (1 - x)^{\frac{1}{2}} d x

\int \frac{1}{e ^{2 x} - 4 e ^{x} + 4} d x

\int 9 x x^{2} + 6 d x

\int x^{\frac{1}{4}} + 7 d x