What is the integral of 9\sqrt[3]{x} ?

The integral of 9\sqrt[3]{x} is 27/4 x^{4/3}+C

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integral of 9\sqrt[3]{x}

\frac{27}{4} x^{\frac{4}{3}} + C

Solution steps

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

Apply the Power Rule

: \frac{3}{4} x^{\frac{4}{3}}

= 9 \cdot \frac{3}{4} x^{\frac{4}{3}}

Simplify

9 \cdot \frac{3}{4} x^{\frac{4}{3}} : \frac{27}{4} x^{\frac{4}{3}}

= \frac{27}{4} x^{\frac{4}{3}}

Add a constant to the solution

= \frac{27}{4} x^{\frac{4}{3}} + C

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What is the integral of 9\sqrt[3]{x} ?
The integral of 9\sqrt[3]{x} is 27/4 x^{4/3}+C