What is the integral of 2x(x^2+3) ?

The integral of 2x(x^2+3) is (x^4)/2+3x^2+C

Popular >

integral of 2x(x^2+3)

\int 2 x (x^{2} + 3) d x

\frac{x ^{4}}{2} + 3 x^{2} + C

Solution steps

\int 2 x (x^{2} + 3) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int x (x^{2} + 3) d x

Expand

x (x^{2} + 3) : x^{3} + 3 x

= 2 \cdot \int x^{3} + 3 x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= 2 (\int x^{3} d x + \int 3 x d x)

\int x^{3} d x = \frac{x ^{4}}{4}

\int 3 x d x = \frac{3 x ^{2}}{2}

= 2 (\frac{x ^{4}}{4} + \frac{3 x ^{2}}{2})

Simplify

2 (\frac{x ^{4}}{4} + \frac{3 x ^{2}}{2}) : \frac{x ^{4}}{2} + 3 x^{2}

= \frac{x ^{4}}{2} + 3 x^{2}

Add a constant to the solution

= \frac{x ^{4}}{2} + 3 x^{2} + C

\int \frac{21}{0.07 x + 5} d x

\int \frac{sin ( 2 x )}{31 + cos ^{2} ( x )} d x

\int (3 + 2 x)^{2} d x

\int \frac{1 + 3 x - x ^{2}}{x ( x - 1 ) ^{2}} d x

\int \frac{1}{t ^{2} + 2} d t