What is the integral of e^{5/x} ?

The integral of e^{5/x} is e^{5/x}x-5\Ei(5/x)+C

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integral of e^{5/x}

\int e^{\frac{5}{x}} d x

e^{\frac{5}{x}} x - 5 Ei (\frac{5}{x}) + C

Solution steps

\int e^{\frac{5}{x}} d x

Apply u-substitution

: \int - \frac{5 e ^{u}}{u ^{2}} d u

= \int - \frac{5 e ^{u}}{u ^{2}} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 5 \cdot \int \frac{e ^{u}}{u ^{2}} d u

Apply Integration By Parts

: - \frac{e ^{u}}{u} - \int - \frac{e ^{u}}{u} d u

= - 5 (- \frac{e ^{u}}{u} - \int - \frac{e ^{u}}{u} d u)

\int - \frac{e ^{u}}{u} d u = - Ei (u)

= - 5 (- \frac{e ^{u}}{u} - (- Ei (u)))

Substitute back

u = \frac{5}{x}

= - 5 (- \frac{e ^{\frac{5}{x}}}{\frac{5}{x}} - (- Ei (\frac{5}{x})))

Simplify

- 5 (- \frac{e ^{\frac{5}{x}}}{\frac{5}{x}} - (- Ei (\frac{5}{x}))) : e^{\frac{5}{x}} x - 5 Ei (\frac{5}{x})

= e^{\frac{5}{x}} x - 5 Ei (\frac{5}{x})

Add a constant to the solution

= e^{\frac{5}{x}} x - 5 Ei (\frac{5}{x}) + C

\frac{1}{x ^{5}}

\int (\frac{1}{x} - \frac{1}{x ^{2}}) d x

\int (\frac{1 - sin ( x )}{1 + sin ( x )}) d x

\int 5 ln (6 x) d x

\int \frac{1}{x ( x - 1 )} d x

What is the integral of e^{5/x} ?
The integral of e^{5/x} is e^{5/x}x-5\Ei(5/x)+C