What is the integral of (-9)/(x(ln(x))^2) ?

The integral of (-9)/(x(ln(x))^2) is 9/(ln(x))+C

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integral of (-9)/(x(ln(x))^2)

\int \frac{- 9}{x ( ln ( x ) ) ^{2}} d x

\frac{9}{ln ( x )} + C

Solution steps

\int \frac{- 9}{x ( ln ( x ) ) ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 9 \cdot \int \frac{1}{x ( ln ( x ) ) ^{2}} d x

Apply u-substitution

: \int \frac{1}{u ^{2}} d u

= - 9 \cdot \int \frac{1}{u ^{2}} d u

Apply the Power Rule

: - \frac{1}{u}

= - 9 (- \frac{1}{u})

Substitute back

u = ln (x)

= - 9 (- \frac{1}{ln ( x )})

Simplify

- 9 (- \frac{1}{ln ( x )}) : \frac{9}{ln ( x )}

= \frac{9}{ln ( x )}

Add a constant to the solution

= \frac{9}{ln ( x )} + C

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What is the integral of (-9)/(x(ln(x))^2) ?
The integral of (-9)/(x(ln(x))^2) is 9/(ln(x))+C