What is the integral of 2/((2x+1)ln(2x+1)) ?

The integral of 2/((2x+1)ln(2x+1)) is ln|ln(2x+1)|+C

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integral of 2/((2x+1)ln(2x+1))

\int \frac{2}{( 2 x + 1 ) ln ( 2 x + 1 )} d x

ln ∣ ln (2 x + 1) ∣ + C

Solution steps

\int \frac{2}{( 2 x + 1 ) ln ( 2 x + 1 )} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int \frac{1}{( 2 x + 1 ) ln ( 2 x + 1 )} d x

Apply u-substitution

: \int \frac{1}{2 u ln ( u )} d u

= 2 \cdot \int \frac{1}{2 u ln ( u )} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \frac{1}{2} \cdot \int \frac{1}{u ln ( u )} d u

Apply u-substitution

: \int \frac{1}{v} d v

= 2 \cdot \frac{1}{2} \cdot \int \frac{1}{v} d v

Use the common integral:

\int \frac{1}{v} d v = ln (∣ v ∣)

= 2 \cdot \frac{1}{2} ln ∣ v ∣

Substitute back

= 2 \cdot \frac{1}{2} ln ∣ ln (2 x + 1) ∣

Simplify

2 \cdot \frac{1}{2} ln ∣ ln (2 x + 1) ∣ : ln ∣ ln (2 x + 1) ∣

= ln ∣ ln (2 x + 1) ∣

Add a constant to the solution

= ln ∣ ln (2 x + 1) ∣ + C

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What is the integral of 2/((2x+1)ln(2x+1)) ?
The integral of 2/((2x+1)ln(2x+1)) is ln|ln(2x+1)|+C