What is the integral of cos(6x+3) ?

The integral of cos(6x+3) is 1/6 sin(6x+3)+C

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integral of cos(6x+3)

\int cos (6 x + 3) d x

\frac{1}{6} sin (6 x + 3) + C

Solution steps

\int cos (6 x + 3) d x

Apply u-substitution

: \int cos (u) \frac{1}{6} d u

= \int cos (u) \frac{1}{6} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{6} \cdot \int cos (u) d u

Use the common integral:

\int cos (u) d u = sin (u)

= \frac{1}{6} sin (u)

Substitute back

u = 6 x + 3

= \frac{1}{6} sin (6 x + 3)

Add a constant to the solution

= \frac{1}{6} sin (6 x + 3) + C

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\int \frac{5 x + 6}{x + 1} d x

What is the integral of cos(6x+3) ?
The integral of cos(6x+3) is 1/6 sin(6x+3)+C